S
ECTION
1.2
Q
UADRATIC
F
UNCTIONS
i) Completing the square
ii) Graphing y=a(x-p)2+q
iii) Using a,p,q to find vertex, opens up, down,
congruency factor,
iv) Deriving and using the quadratic function
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I) G
RAPHING
QF:
A Quadratic function in standard form is much easier
to graph
Using constants “a”,”p”, & “q”, we can find the vertex,
which way it opens and the congruency value
Vertex:
Axis of Symmetry:
Domain:
Range:
Y intercept: make x=0, solve for y
X-intercept: make y=0, solve for x
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E
X
: F
OR
EACH
OF
FOLLOWING
EQUATIONS
,
FIND
THE
CONSTANTS
“
A
”, “
P
”, “
Q
”,
VERTEX
,
AND
A.O.S.
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II) C
ONSTANTS
“P”
AND
“Q”
The constant “p” affects the graph horizontally
When
p=0
, the graph is centered on the Y-axis
x
y
0
x
y
0
x
y
0
2 units
Right
2 units
Left
x
y
0
x
y
0
2 units
up
2 units
Down
Interactive
Applet
The constant “q” affects the graph vertically
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G
RAPH
:
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III) H
OW
DOES
THE
CONSTANT
“
A
”
WORK
?
5
5
3
3
1
1
Beginning at the vertex
we can graph all the
other points without
making a TOV
Each point increases
horizontally by 1
but increases vertically
by 1 , 3 , 5 , 7 , 9, …
7
7
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6
10
10
6
2
2
If “a = 2”, the points
go up faster.
Each point increases
horizontally by 1
but increases vertically
by 2 , 6 , 10 , 14 , 18, …
Simply multiply the
values by “2”
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IV) C
ONSTANT
“
A
” (C
ONGRUENCY
F
ACTOR
)
The constant “a” determines the (congruency) width of
the parabola and which way it opens
If “a” is positive (Opens up)
If ‘a” is negative (Opens down)
If “a” is big (Skinny)
If “a” is small (Wide)
Congruency Factor:
The constant “a” can be used to determine how fast
the points on the parabola go up by
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P
RACTICE
: G
RAPH
THE
FOLLOWING
P
ARABOLAS
AND
I
NDICATE
THE
V
ERTEX
, AOS, D
OMAIN
& R
ANGE
2
6
10
3.5
2.5
1.5
0.5
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VI) CTS: C
OMPLETE
THE
S
QUARE
!
Completing the Square is a process that changes a
quadratic functions from
General form:
Standard Form:
Bracket the first two terms!
Divide the second term by 2 and
square it! The purpose is to make the
expression in the bracket into a
perfect square!
Take the negative square outside of
the brackets!
The trinomial becomes two equal
binomials
Standard Form!
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P
RACTICE
: C
ONVERT
THE
FOLLOWING
TO
STANDARD
F
ORM
Bracket the first two terms!
Divide the second term by 2 and
square it!
Take the negative square outside of
the brackets and multiply with
coefficient in front!
The trinomial becomes two equal
binomials
Standard Form!
Factor out any coefficient for x
2
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H
OMEWORK
: A
SSIGNMENT
1.2
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