P
RE
C
ALCULUS
11
S
ECTION
1.4
G
EOMETRIC
S
ERIES
i) Sums of a geometric series and infinite
geometric series
ii) Deriving the formula for the sum of a
geometric series and infinite geometric series
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D
EFINITION
: G
EOMETRIC
S
ERIES
A geometric series is the
sum
[
addition
] of the
terms in a
geometric sequence
Consider the geometric sequence 1, 2, 4, 8, 16,
32, 64, 128, 256, 512, 1024 .
If we add the terms of the sequence, we can
write the geometric series as
In
this section we will learn to find the value of
a geometric series
II) S
UM
OF
G
EOMETRIC
S
EQUENCE
:
Sum of a geometric series up to the
n
th
term
Multiply both sides by
“r”
Subtract the equations!
Factor out
“S
n
”
Divide both sides by (
1
-
r
)
Factor out
“a”
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A
LTERNATIVE
E
QUATION
:
Since the last term
t
n
is:
We can rewrite the equation as:
The sum of a
geometric series
from the first term to
the
n
th
term
First
term (a)
Common ratio times
the last term
One minus the common ratio
Sum of the first 2 terms
Sum of the first 5 terms
E
X
: F
IND
THE
SUM
OF
THE
FOLLOWING
G
EOMETRIC
S
EQUENCE
:
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P
RACTICE
:
D
ETERMINE
THE
SUM
OF
14
TERMS
OF
THE
GEOMETRIC
SERIES
:
S
= 6 + 18 + 54 + …
II
)
FIND
THE
SUM
OF
THE
FIRST
20
TERMS
.
E
XAMPLE
4:
D
ETERMINE
THE
N
TH
TERM
,
AND
THE
SUM
OF
THE
FIRST
N
TERMS
OF
THE
GEOMETRIC
SEQUENCE
WHICH
HAS
2, 6,
AND
18
AS
ITS
FIRST
THREE
NUMBERS
.
The general term is an equation in terms of “n”. The
value of the Geometric series varies as the value of “n”
changes
E
X
: F
IND
THE
S
UM
:
First find out
how many terms
there are
Then find the
sum up to the
“14
th
”term
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Since “n” is a whole
number we can guess and
check
Jason gave his son a penny on the first day of the month
and doubled the amount each day. How much money
will he give his son altogether by the 30
th
day?
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E
XAMPLE
5:
T
HE
FOLLOWING
IS
A
SCHOOL
TRIP
TELEPHONING
TREE
.
Level 1: Teacher
Level 2: Students
Level 3: Students
a) At what level are 64 students contacted?
r
= 2; (Each student contacts 2 students.)
Find n
.
B
) H
OW
MANY
ARE
CONTACTED
AT
THE
8
TH
LEVEL
?
Remember that the teacher is not counted. So we will subtract 1
from the total
S
8
.
The total number of students
contacted is
255 – 1 = 254 .
C) By the 8
th
level, how many students, in total, have been contacted?
D
) B
Y
THE
N
TH
LEVEL
,
HOW
MANY
STUDENTS
,
IN
TOTAL
,
HAVE
BEEN
CONTACTED
?
Again, remember that the teacher is not counted.
So we will simply subtract 1 from the sum up to level n.
The total number of students by level n is given by
e)
If there are 300 students in total, by what level will all have been
contacted?
Since 254 students have been contacted by level 8,
then all 300 will have been telephoned by level 9.
E
X
: A
RUBBER
BALL
IS
DROPPED
FROM
A
HEIGHT
OF
10
M
. A
FTER
EACH
BOUNCE
,
THE
BALL
RETURNS
TO
65%
OF
ITS
PREVIOUS
HEIGHT
. C
ALCULATE
ALL
THE
VERTICAL
DISPLACEMENT
RIGHT
BEFORE
THE
8
TH
BOUNCE
.
Note: There are two types of
displacement: Going up and down
Each displacement is doubled
except the first bounce
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C
HALLENGE
:
THE
SUM
OF
THE
SECOND
& T
HIRD
TERM
IN
A
GEOMETRIC
SERIES
IS
45. T
HE
SUM
OF
THE
FOURTH
& F
IFTH
TERM
IS
20. F
IND
THE
GEOMETRIC
SEQUENCE
:
The 4
th
and 5
th
terms add to 20
The 2
nd
and 3
rd
terms add to 45
Factor out any common factors
In each equation
Divide the equations
Use the common ratio to find the first term
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Find the 2
nd
series when the
common ratio is negative
H
OMEWORK
:
Assignment 1.4